Hướng dẫn giải của Gặm cỏ
Chỉ dùng lời giải này khi không có ý tưởng, và đừng copy-paste code từ lời giải này. Hãy tôn trọng người ra đề và người viết lời giải.
Nộp một lời giải chính thức trước khi tự giải là một hành động có thể bị ban.
Nộp một lời giải chính thức trước khi tự giải là một hành động có thể bị ban.
Lưu ý: Các code mẫu dưới đây chỉ mang tính tham khảo và có thể không AC được bài tập này
Code mẫu của flashmt
const dx:array[1..4] of shortint=(-1,0,1,0); dy:array[1..4] of shortint=(0,1,0,-1); var m,n,sx,sy:byte; a:array[1..100,1..100] of char; d:array[1..100,1..100] of word; q:array[1..10000,0..1] of byte; procedure wf; begin write(d[1,1]-1); end; procedure rf; var I,j:byte; begin readln(m,n); for i:=1 to m do begin for j:=1 to n do begin read(a[i,j]); if a[i,j]='C' then begin sx:=i; sy:=j; end; end; readlN; end; end; function check(x,y:byte):boolean; begin check:=(x>0) and (x<=m) and (y>0) and (y<=n); end; procedure pr; var i,num:integer; x,y,j:byte; begin fillchar(d,sizeof(d),0); num:=1; i:=1; q[1,0]:=sx; q[1,1]:=sy; d[sx,sy]:=1; repeat for j:=1 to 4 do begin x:=q[i,0]+dx[j]; y:=q[i,1]+dy[j]; if check(x,y) and ((a[x,y]='.') or (a[x,y]='B')) and (d[x,y]=0) then begin inc(num); q[num,0]:=x; q[num,1]:=y; d[x,y]:=d[q[i,0],q[i,1]]+1; end; end; inc(i); until (d[1,1]>0); end; begin rf; pr; wf; end.
Code mẫu của happyboy99x
#include <algorithm> #include <bitset> #include <cctype> #include <cfloat> #include <climits> #include <cmath> #include <complex> #include <cstdio> #include <cstdlib> #include <cstring> #include <ctime> #include <deque> #include <functional> #include <list> #include <map> #include <numeric> #include <queue> #include <set> #include <stack> #include <string> #include <utility> #include <vector> using namespace std; typedef pair<int, int> ii; typedef vector<ii> vii; typedef vector<vii> vvii; typedef vector<int> vi; typedef vector<vi> vvi; #define sz(a) int((a).size()) #define fi first #define se second #define pb push_back #define mp make_pair #define all(c) (c).begin(), (c).end() #define tr(c,i) for(typeof((c).begin()) i = (c).begin(), _e = (c).end(); it != _e; ++it) #define present(c,x) ((c).find(x) != (c).end()) #define cpresent(c,x) (find(all(c),x) != (c).end()) #define rep(i,n) for(int i = 0, _n = (n); i < _n; ++i) #define repd(i,n) for(int i = (n)-1; i >= 0; --i ) #define fo(i,a,b) for(int i = (a), _b = (b); i <= _b; ++i) #define fod(i,a,b) for(int i = (a), _b = (b); i >= _b; --i) #define INF 1000000000 #define N 1005 int r, c; char a[N][N]; bool ch[N][N]; int I[4] = {-1, 0, 0, 1}, J[4] = {0, -1, 1, 0}; int main() { //freopen( "input.txt", "r", stdin ); //freopen( "output.txt", "w", stdout ); scanf( "%d%d\n", &r, &c ); rep(i, r) gets(a[i]); queue<ii> qu; bool stop = false; for( int i = 0; i < r && !stop; ++i ) rep(j, c) if( a[i][j] == 'C' ) { ch[i][j] = 1; qu.push(mp(i,j)); stop = 1; break; } for( int step = 0; !qu.empty(); ++step ) { rep(i, qu.size()) { int x = qu.front().fi, y = qu.front().se; qu.pop(); if( a[x][y] == 'B' ) { printf( "%d\n", step ); return 0; } rep(k, 4) { int xx = x + I[k], yy = y + J[k]; if( xx >= 0 && yy >= 0 && xx < r && yy < c && ch[xx][yy] == 0 && a[xx][yy] != '*') { ch[xx][yy] = 1; qu.push(mp(xx,yy)); } } } } return 0; }
Code mẫu của ladpro98
Program VMUNCH; Const fi=''; fo=''; wx:array[1..4] of integer=(-1,1,0,0); wy:array[1..4] of integer=(0,0,1,-1); Var a:array[0..123,0..123] of longint; r,c,x,y,count:longint; f:text; Procedure INPUT; Var i,j:longint; t:char; Begin Assign(f,fi); Reset(f); readln(f,r,c); For i:=0 to r+1 do For j:=0 to c+1 do a[i,j]:=1; a[1,1]:=0; For i:=1 to r do begin For j:=1 to c do begin read(f,t); If t='.' then a[i,j]:=0; If t='C' then begin x:=i; y:=j; a[x,y]:=0; End; End; Readln(f); End; Close(f); End; Procedure FIND; var dem,first,last,k,i,j:longint; tx,ty,c:array[1..10001] of longint; Begin first:=1; last:=1; Fillchar(tx,sizeof(tx),0); Fillchar(ty,sizeof(ty),0); Fillchar(c,sizeof(c),0); tx[1]:=1;ty[1]:=1;a[1,1]:=1;c[1]:=1; dem:=0; While first<=last do begin i:=tx[first]; j:=ty[first]; For k:=1 to 4 do if a[i+wx[k],j+wy[k]]=0 then begin a[i+wx[k],j+wy[k]]:=c[first]+1; inc(last); tx[last]:=i+wx[k]; ty[last]:=j+wy[k]; c[last]:=c[first]+1; If a[x,y]<>0 then begin count:=a[x,y]-1; Exit; End; End; inc(first); End; End; Procedure OUTPUT; Begin Assign(f,fo); Rewrite(f); Writeln(f,count); Close(f); End; BEGIN INPUT; FIND; OUTPUT; END.
Code mẫu của RR
uses math; const MAXN=111; var m,n,i,j,su,sv,tu,tv,u,v,uu,vv,di,dj:longint; a:array[1..MAXN,1..MAXN] of char; d:array[1..MAXN,1..MAXN] of longint; qu,qv:array[1..MAXN*MAXN] of longint; first,last:longint; begin readln(m,n); for i:=1 to m do begin for j:=1 to n do begin read(a[i,j]); if a[i,j]='B' then begin tu:=i; tv:=j; end; if a[i,j]='C' then begin su:=i; sv:=j; end; end; readln; end; first:=1; last:=1; qu[1]:=su; qv[1]:=sv; d[su,sv]:=1; while first<=last do begin u:=qu[first]; v:=qv[first]; inc(first); for di:=-1 to 1 do for dj:=-1 to 1 do if di*di+dj*dj=1 then begin uu:=u+di; vv:=v+dj; if (uu>0) and (vv>0) and (uu<=m) and (vv<=n) and (d[uu,vv]=0) and (a[uu,vv]<>'*') then begin d[uu,vv]:=d[u,v]+1; inc(last); qu[last]:=uu; qv[last]:=vv; end; end; end; writeln(d[tu,tv]-1); end.
Code mẫu của hieult
#include <stdio.h> //#include <conio.h> int n,m,a[101][101],f[101][101],x1,y1,x2,y2,so = 1,x[10001],y[10001]; char s[101][101]; int check(int u,int v) { if(u>=0 && u<n && v>=0 && v<m && a[u][v]==0) return 1; else return 0; // printf("%d %d %d %d\n",u,v,n,m); } int xuly(int j,int i) { int u,v; v = j-1;u = i; if( check(u,v) == 1) { f[u][v] = f[i][j]+1; a[u][v]=1; so++; x[so] = v; y[so] = u; //printf("",so); // printf("%d %d %d\n",so,u,v); } v = j+1;u = i; if( check(u,v) == 1) { f[u][v] = f[i][j]+1; a[u][v]=1; so++; x[so] = v; y[so] = u; // printf("",so); // printf("%d %d %d\n",so,u,v); } v = j;u = i+1; if( check(u,v) == 1) { f[u][v] = f[i][j]+1; a[u][v]=1; so++; x[so] = v; y[so] = u; // printf("%d %d %d\n",so,u,v); // printf("",so); } v = j;u = i-1; if( check(u,v) == 1) { f[u][v] = f[i][j]+1; a[u][v]=1; so++; x[so] = v; y[so] = u; // printf("",so); // printf("%d %d %d\n",so,u,v); } } int main() { //freopen("VMUNCH.in","r",stdin); scanf("%d %d",&n,&m); for(int i = 0;i<n;i++) { scanf("%s",s[i]); for(int j = 0;j<m;j++) { a[i][j] = 0;f[i][j]=-1; if(s[i][j] == 'B') { x1 = j;y1=i;a[i][j]=1,f[i][j]=0,x[1]=j,y[1]=i;} else if(s[i][j] == 'C') { x2 = j; y2= i;} else if(s[i][j]=='*') a[i][j] = 1; // printf("%d ",a[i][j]); } // printf("\n%d %d %d %d",x1,y1,x2,y2); //printf("\n"); } for(int i = 1;;i++) { // printf("%d %d %d\n",i,x[i],y[i]); if(f[y2][x2]>=0) break; else xuly(x[i],y[i]); } printf("%d",f[y2][x2]); //getch(); }
Code mẫu của ll931110
Program VMUNCH; Const input = ''; output = ''; Var s: array[0..101,0..101] of boolean; adj,head,trace: array[0..30000] of integer; r,c: integer; start,finish: integer; Procedure LoadGraph; Var f: text; i,j: integer; ch: char; Begin Assign(f, input); Reset(f); Readln(f, r, c); Fillchar(s, sizeof(s), false); For i:= 1 to r do Begin For j:= 1 to c do Begin Read(f, ch); Case ch of '.': s[i,j]:= true; 'C': Begin start:= c * (i - 1) + j; s[i,j]:= true; End; 'B': Begin finish:= c * (i - 1) + j; s[i,j]:= true; End; End; End; readln(f); End; Close(f); End; Procedure init; Var numadj,i,j: longint; Begin numadj:= 0; For i:= 1 to r do For j:= 1 to c do Begin Head[c * (i - 1) + j]:= numadj; If s[i,j] then Begin If s[i - 1,j] then Begin inc(numadj); adj[numadj]:= c * (i - 2) + j; End; If s[i,j - 1] then Begin inc(numadj); adj[numadj]:= c * (i - 1) + (j - 1); End; If s[i,j + 1] then Begin inc(numadj); adj[numadj]:= c * (i - 1) + (j + 1); End; If s[i + 1,j] then Begin inc(numadj); adj[numadj]:= c * i + j; End; End; End; head[r * c + 1]:= numadj; End; Procedure BFS; Var Queue: array[1..30000] of integer; front,rear,u,v: integer; Begin front:= 1; rear:= 1; Queue[1]:= start; Fillchar(trace, sizeof(trace), 0); trace[start]:= -1; Repeat u:= Queue[front]; inc(front); For v:= head[u] + 1 to head[u + 1] do if trace[adj[v]] = 0 then Begin inc(rear); queue[rear]:= adj[v]; trace[adj[v]]:= u; End; Until front > rear; End; Procedure solve; Var f: text; num: integer; Begin Assign(f, output); Rewrite(f); num:= 0; While finish <> start do Begin inc(num); finish:= trace[finish]; End; Writeln(f, num); Close(f); End; Begin LoadGraph; init; BFS; solve; End.
Code mẫu của skyvn97
#include<stdio.h> #include<queue> #define MAX 111 using namespace std; typedef pair<int,int> ii; int c[MAX][MAX]; int l[MAX][MAX]; int m,n; ii s,e; int dx[]={0,1,0,-1}; int dy[]={1,0,-1,0}; void init(void) { scanf("%d",&m); scanf("%d",&n); int i,j; char t[MAX]; for (i=0;i<=m+1;i=i+1) { c[i][0]=2; c[i][n+1]=2; } for (i=0;i<=n+1;i=i+1) { c[0][i]=2; c[m+1][i]=2; } for (i=1;i<=m;i=i+1) for (j=1;j<=n;j=j+1) { c[i][j]=0; l[i][j]=0; } for (i=1;i<=m;i=i+1) { scanf("%s",t); for (j=1;j<=n;j=j+1) { if (t[j-1]=='*') c[i][j]=2; if (t[j-1]=='B') s=ii(i,j); if (t[j-1]=='C') e=ii(i,j); } } } void bfs(void) { queue<ii> q; c[s.first][s.second]=1; ii t; int i,x,y; q.push(s); while (!q.empty()) { t=q.front(); q.pop(); x=t.first; y=t.second; if (t==e) { printf("%d",l[x][y]); return; } for (i=0;i<4;i=i+1) if (c[x+dx[i]][y+dy[i]]==0) { c[x+dx[i]][y+dy[i]]=1; l[x+dx[i]][y+dy[i]]=l[x][y]+1; q.push(ii(x+dx[i],y+dy[i])); } } } int main(void) { init(); bfs(); }
Code mẫu của khuc_tuan
#include <iostream> #include <queue> #include <algorithm> using namespace std; int m, n; char a[111][111]; queue< pair<int,int> > q; pair<int,int> f[111][111]; int main() { scanf("%d%d", &m, &n); gets(a[0]); for(int i=0;i<m;++i) gets(a[i]); for(int i=0;i<111;++i) for(int j=0;j<111;++j) f[i][j] = make_pair( 11111, 0); for(int i=0;i<m;++i) for(int j=0;j<n;++j) if(a[i][j]=='C') { q.push( make_pair( i, j)); f[i][j] = make_pair( 0, -1); } while(!q.empty()) { int u = q.front().first; int v = q.front().second; q.pop(); for(int dx=-1;dx<=1;++dx) for(int dy=-1;dy<=1;++dy) if((dx!=0) ^ (dy!=0)) { int x = u + dx; int y = v + dy; if(x<0 || x>=m || y<0 || y>=n) continue; if(a[x][y]=='*') continue; int t = a[x][y]=='.' ? -1 : 0; if(f[x][y] > make_pair( f[u][v].first+1, f[u][v].second+t)) { f[x][y] = make_pair(f[u][v].first+1, f[u][v].second+t); q.push( make_pair( x, y)); } } } for(int i=0;i<m;++i) for(int j=0;j<n;++j) if(a[i][j]=='B') { cout << -f[i][j].second << endl; } //system("pause"); return 0; }
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