Editorial for EXPAR


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Submitting an official solution before solving the problem yourself is a bannable offence.

Lưu ý: Các code mẫu dưới đây chỉ mang tính tham khảo và có thể không AC được bài tập này

Code mẫu của ladpro98

#include <cstring>
#include <vector>
#include <list>
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <stack>
#include <bitset>
#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <sstream>
#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <climits>
#include <cstdlib>
#include <ctime>
#include <memory.h>
#include <cassert>
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define REP(i, a, b) for(int i = (a); i <=(b); i++)
#define FORD(i, a, b) for(int i = (a); i > (b); i--)
#define REPD(i, a, b) for(int i = (a); i >=(b); i--)
#define SZ(a) (int((a).size()))
#define ALL(a) (a).begin(), (a).end()
#define PB push_back
#define MP make_pair
#define LL long long
#define LD long double
#define II pair<int, int>
#define X first
#define Y second
#define VI vector<int>

using namespace std;
string s, e, px, py;
char x, y;

bool isDigit(char x) {return '0' <= x && x <= '9';}
bool is0(char x) {return isDigit(x) && (x - '0' & 1) == 0;}
int parseInt(string s)
    {int a = 0; FOR(i, 0, SZ(s)) a = 10 * a + s[i] - '0'; return a;}

int main() {
    ios :: sync_with_stdio(0); cin.tie(0);
    cin >> s; cin >> px; cin >> py;
    if (px == "Odd") x = '1'; else x = '0';
    if (py == "Odd") y = '1'; else y = '0';
    int n = SZ(s);
    FOR(i, 0, n) {
        if (s[i] == 'x') s[i] = x;
        if (s[i] == 'y') s[i] = y;
    }
    e = "+";
    for(int i = 0; i < SZ(s); ) {
        if (isDigit(s[i])) {
            int j = i;
            while (j < SZ(s) - 1 && isDigit(s[j + 1])) j++;
            e += char('0' + (parseInt(s.substr(i, j - i + 1)) & 1));
            i = j + 1;
        }
        else {
            if (s[i] == '-') s[i] = '+';
            e += s[i];
            i++;
        }
    }
    e += '+';
    //cout << e << endl;
    int ans = 0;
    for(int i = 0; i < SZ(e) - 1; )
    if (e[i] == '+') {
        int j = i + 1;
        while (e[j] != '+') j++;
        bool isOdd = 1;
        FOR(k, i, j) if (is0(e[k])) {
            isOdd = 0; break;
        }
        ans += isOdd;
        i = j;
    }
    else i++;
    if (ans & 1) cout << "Odd"; else cout << "Even";
    return 0;
}

Code mẫu của RR

#include <set>
#include <map>
#include <list>
#include <cmath>
#include <queue>
#include <stack>
#include <cstdio>
#include <string>
#include <vector>
#include <cstdlib>
#include <cstring>
#include <sstream>
#include <iomanip>
#include <complex>
#include <iostream>
#include <algorithm>

#include <ctime>
#include <deque>
#include <bitset>
#include <cctype>
#include <utility>
#include <cassert>
using namespace std;

#define FOR(i,a,b) for(int i=(a),_b=(b); i<=_b; i++)
#define FORD(i,a,b) for(int i=(a),_b=(b); i>=_b; i--)
#define REP(i,a) for(int i=0,_a=(a); i<_a; i++)
#define EACH(it,a) for(__typeof(a.begin()) it = a.begin(); it != a.end(); ++it)
#define SZ(S) ((int) ((S).size()))

#define DEBUG(x) { cout << #x << " = " << x << endl; }
#define PR(a,n) { cout << #a << " = "; FOR(_,1,n) cout << a[_] << ' '; cout << endl; }
#define PR0(a,n) { cout << #a << " = "; REP(_,n) cout << a[_] << ' '; cout << endl; }

int main() {
    ios :: sync_with_stdio(false); cin.tie(NULL);
    cout << (fixed) << setprecision(6);
    string s, a, b;
    while (cin >> s >> a >> b) {
        int x = (a[0] == 'O') ? 1 : 0;
        int y = (b[0] == 'O') ? 1 : 0;

        REP(i,s.length()) if (s[i] == '+' || s[i] == '-') s[i] = ' ';
        REP(i,s.length()) if (s[i] == 'x') s[i] = '0' + x;
        REP(i,s.length()) if (s[i] == 'y') s[i] = '0' + y;

        string t;
        stringstream ss(s);
        int res = 0;
        while (ss >> t) {
            REP(i,t.length()) if (t[i] == '*') t[i] = ' ';
            stringstream ss2(t);

            int prod = 1;
            string cur;
            while (ss2 >> cur) {
                prod = (prod * (cur[cur.size()-1] - '0')) % 2;
            }
            res = (res + prod) % 2;
        }
        if (res % 2) cout << "Odd"; else cout << "Even";
        cout << endl;
    }
    return 0;
}

Code mẫu của skyvn97

#include<bits/stdc++.h>
#define REP(i,n) for (int i=0,_n=(n);i<_n;i=i+1)
using namespace std;
const string odd="Odd";
const string even="Even";
queue<char> inp;
bool loadExpLv1(void) {
    assert(!inp.empty());
    char c=inp.front();inp.pop();
    assert(c=='0'||c=='1');
    return (c=='1');
}
bool loadExpLv2(void) {
    bool res=loadExpLv1();
    while (!inp.empty() && inp.front()=='&') {
        inp.pop();
        res&=loadExpLv1();
    }
    return (res);
}
bool loadExpLv3(void) {
    bool res=loadExpLv2();
    while (!inp.empty() && inp.front()=='^') {
        inp.pop();
        res^=loadExpLv2();
    }
    return (res);
}
int main(void) {
    string s,x,y;
    cin>>s>>x>>y;
    REP(i,s.size()) {
        if ('0'<=s[i] && s[i]<='9') {
            if (i+1<s.size() && '0'<=s[i+1] && s[i+1]<='9') continue;
            inp.push((s[i]-'0')%2+'0');
        }
        if (s[i]=='x') inp.push((x==odd)+'0');
        if (s[i]=='y') inp.push((y==odd)+'0');
        if (s[i]=='+' || s[i]=='-') inp.push('^');
        if (s[i]=='*') inp.push('&');
    }
    cout<<(loadExpLv3()?odd:even);
    return 0;
}

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