Hướng dẫn giải của Học sử
Chỉ dùng lời giải này khi không có ý tưởng, và đừng copy-paste code từ lời giải này. Hãy tôn trọng người ra đề và người viết lời giải.
Nộp một lời giải chính thức trước khi tự giải là một hành động có thể bị ban.
Nộp một lời giải chính thức trước khi tự giải là một hành động có thể bị ban.
Lưu ý: Các code mẫu dưới đây chỉ mang tính tham khảo và có thể không AC được bài tập này
Code mẫu của flashmt
#include <iostream> #include <algorithm> #include <cstdio> #include <vector> #define N 100100 using namespace std; int n,cnt,sm,last,re,st[N],dis[N],low[N],f[N],g[N],d[N]; vector <int> a[N],b[N]; void visit(int x,int par) { dis[x]=low[x]=++cnt; st[++last]=x; for (int i=0;i<int(a[x].size());i++) if (!d[a[x][i]] && a[x][i]!=par) { if (dis[a[x][i]]) low[x]=min(low[x],dis[a[x][i]]); else visit(a[x][i],x), low[x]=min(low[x],low[a[x][i]]); } if (low[x]<dis[x]) return; ++sm; for (;;) { int y=st[last--]; d[y]=sm; if (x==y) return; } } void calc(int x,int par) { int extra=int(1e9),u=0; d[x]=0; if (b[x].empty() || (b[x].size()==1 && par)) return; for (int i=0;i<int(b[x].size());i++) { int y=b[x][i]; if (y==par) continue; calc(y,x); u+=g[y]; extra=min(extra,f[y]-g[y]); } g[x]=min(f[x],u+extra); f[par]+=min(g[x],u); } int main() { int m,x,y; cin >> n >> m; while (m--) { scanf("%d%d",&x,&y); a[x].push_back(y); a[y].push_back(x); } for (int i=1;i<=n;i++) if (!d[i]) visit(i,0); for (int x=1;x<=n;x++) for (int i=0;i<int(a[x].size());i++) if (d[a[x][i]]!=d[x]) b[d[x]].push_back(d[a[x][i]]); for (int i=1;i<=sm;i++) f[i]=g[i]=1; for (int i=1;i<=sm;i++) if (d[i]) calc(i,0), re+=g[i]; cout << re << endl; return 0; }
Code mẫu của happyboy99x
#include<algorithm> #include<iostream> #include<cstring> #include<cassert> #include<vector> #include<cstdio> #include<queue> using namespace std; const int N = 1e5, M = 1e5, INF = 1e9; vector<pair<int, int> > graph[N]; bool isBridge[M], vst[N]; int discover[N], low[N], parent[N], f[N][3], ttime, n, m; template<class T> ostream& operator << (ostream &out, const pair<T, T> &x) { return out << '(' << x.first << ", " << x.second << ')'; } void enter() { cin >> n >> m; for(int i = 0; i < m; ++i) { int u, v; cin >> u >> v; --u; --v; graph[u].push_back(make_pair(v, i)); graph[v].push_back(make_pair(u, i)); } } void dfs(int u) { discover[u] = low[u] = ttime++; for(unsigned i = 0; i < graph[u].size(); ++i) { int v = graph[u][i].first, e = graph[u][i].second; if(discover[v] == -1) { parent[v] = u; dfs(v); low[u] = min(low[u], low[v]); isBridge[e] = low[v] >= discover[v]; } else if(v != parent[u]) { low[u] = min(low[u], discover[v]); } } } void calcF(int u) { vector<int> child; queue<int> q; q.push(u); vst[u] = true; while(!q.empty()) { int u = q.front(); q.pop(); for(unsigned i = 0; i < graph[u].size(); ++i) { int v = graph[u][i].first, e = graph[u][i].second; if(vst[v]) continue; if(isBridge[e]) { child.push_back(v); } else { q.push(v); vst[v] = true; } } } if(child.empty()) { f[u][0] = 0; // parent[u] is in set f[u][1] = 1; // u is in set f[u][2] = INF; // at least one child of u is in set } else { f[u][0] = 0; f[u][1] = 1; f[u][2] = 0; int lambda = INF; for(unsigned i = 0; i < child.size(); ++i) { int v = child[i]; calcF(v); f[u][1] += f[v][0]; f[u][2] += min(f[v][1], f[v][2]); lambda = min(lambda, f[v][1] - min(f[v][1], f[v][2])); } f[u][0] = min(f[u][1], f[u][2]); f[u][2] += lambda; } } void solve() { memset(discover, -1, sizeof discover); memset(parent, -1, sizeof parent); int res = 0; for(int s = 0; s < n; ++s) { if(discover[s] == -1) { dfs(s); calcF(s); res += min(f[s][1], f[s][2]); } } cout << res << endl; } int main() { #ifdef __DNK__ assert(freopen("input.txt", "r", stdin)); #endif ios::sync_with_stdio(false); enter(); solve(); return 0; }
Code mẫu của ladpro98
#include <cstring> #include <vector> #include <list> #include <map> #include <set> #include <queue> #include <deque> #include <stack> #include <bitset> #include <algorithm> #include <functional> #include <numeric> #include <utility> #include <sstream> #include <iostream> #include <iomanip> #include <cstdio> #include <cmath> #include <climits> #include <cstdlib> #include <ctime> #include <memory.h> #include <cassert> #define FOR(i, a, b) for(int i = (a); i < (b); i++) #define REP(i, a, b) for(int i = (a); i <=(b); i++) #define FORD(i, a, b) for(int i = (a); i > (b); i--) #define REPD(i, a, b) for(int i = (a); i >=(b); i--) #define SZ(a) (int((a).size())) #define ALL(a) (a).begin(), (a).end() #define PB push_back #define MP make_pair #define LL long long #define LD long double #define II pair<int, int> #define X first #define Y second #define VI vector<int> const int N = 100005; const int oo = 1000000000; using namespace std; bool was[N]; int num[N], low[N], lab[N], F[3][N]; VI a[N], adj[N]; int n, m, timer, nNode; stack<int> S; void build(int u, int par) { num[u] = ++timer; low[u] = oo; S.push(u); int v; FOR(i, 0, SZ(a[u])) { v = a[u][i]; if (was[v] || v == par) continue; if (num[v]) low[u] = min(low[u], num[v]); else { build(v, u); low[u] = min(low[u], low[v]); } } if (low[u] >= num[u]) { ++nNode; do { v = S.top(); S.pop(); was[v] = 1; lab[v] = nNode; } while (v != u); } } void minimize(int &a, int b) {a = a > b ? b : a;} void DP(int u, int par) { was[u] = 1; FOR(i, 0, SZ(adj[u])) if (adj[u][i] != par) DP(adj[u][i], u); F[0][u] = 1; F[1][u] = 0; FOR(i, 0, SZ(adj[u])) { int v = adj[u][i]; if (v == par) continue; F[0][u] += F[1][v]; F[1][u] += F[2][v]; } F[2][u] = F[0][u]; FOR(i, 0, SZ(adj[u])) if (adj[u][i] != par) minimize(F[2][u], F[1][u] - F[2][adj[u][i]] + F[0][adj[u][i]]); minimize(F[1][u], F[0][u]); } int main() { ios :: sync_with_stdio(0); cin.tie(0); cin >> n >> m; int u, v; FOR(i, 0, m) { cin >> u >> v; a[u].PB(v); a[v].PB(u); } REP(i, 1, n) if (!was[i]) build(i, 0); REP(i, 1, n) FOR(j, 0, SZ(a[i])) if (lab[i] != lab[a[i][j]]) adj[lab[i]].PB(lab[a[i][j]]), adj[lab[a[i][j]]].PB(lab[i]); REP(i, 1, nNode) { was[i] = 0; sort(ALL(adj[i])); int newSize = unique(ALL(adj[i])) - adj[i].begin(); adj[i].resize(newSize); } int ans = 0; REP(i, 1, nNode) if (!was[i]) { was[i] = 1; DP(i, 0); ans += F[2][i]; } cout << ans; return 0; }
Code mẫu của RR
#include <cstdio> #include <iostream> #include <algorithm> #include <vector> #include <queue> #include <stack> #include <set> #include <map> #include <cstring> #include <cstdlib> #include <cmath> #include <string> #include <memory.h> #include <sstream> #include <complex> #include <iomanip> #define REP(i,n) for(int i = 0, _n = (n); i < _n; i++) #define REPD(i,n) for(int i = (n) - 1; i >= 0; i--) #define FOR(i,a,b) for (int i = (a), _b = (b); i <= _b; i++) #define FORD(i,a,b) for (int i = (a), _b = (b); i >= _b; i--) #define FOREACH(it,c) for (__typeof((c).begin()) it=(c).begin();it!=(c).end();it++) #define RESET(c,x) memset (c, x, sizeof (c)) #define sqr(x) ((x) * (x)) #define PB push_back #define MP make_pair #define F first #define S second #define ALL(c) (c).begin(), (c).end() #define SIZE(c) (c).size() #define DEBUG(x) { cout << #x << " = " << x << endl; } #define PR(a,n) {cout<<#a<<" = "; FOR(_,1,n) cout << a[_] << ' '; cout <<endl;} #define PR0(a,n) {cout<<#a<<" = ";REP(_,n) cout << a[_] << ' '; cout << endl;} using namespace std; const double PI = 2.0 * acos (0.0); typedef long long LL; typedef pair <int, int> PII; template <class T> inline T MAX (T a, T b) { if (a > b) return a; return b; } template <class T> inline T MIN (T a, T b) { if (a < b) return a; return b; } // ptrrsn_1's template const int MN = 100111; int n, m, low[MN], num[MN], reg[MN], st[MN], top, now, nReg, ls[MN], sz, res; vector< int > ke[MN], ke2[MN]; int f[3][MN]; void init() { memset(num, 0, sizeof num); memset(reg, 0, sizeof reg); top = now = res = 0; FOR(i,1,n) ke[i].clear(); } void dfs1(int u, int fu) { ++now; low[u] = num[u] = now; st[++top] = u; ls[++sz] = u; REP(i,ke[u].size()) { int v = ke[u][i]; if (v == fu) continue; if (!num[v]) { dfs1(v, u); low[u] = min(low[u], low[v]); } else low[u] = min(low[u], num[v]); } if (low[u] == num[u]) { ++nReg; while (st[top] != u) { reg[st[top--]] = nReg; } reg[st[top--]] = nReg; } } void dfs2(int u, int fu) { f[0][u] = 0; // Khong to mau u, u thoa man f[1][u] = 1; // Co' to mau u, u thoa man f[2][u] = 0; // Khong to mau u, u ko thoa man, con u thoa man bool isLeaf = true, has = false; int nn = 1000111000; REP(i,ke2[u].size()) { int v = ke2[u][i]; if (v == fu) continue; isLeaf = false; dfs2(v, u); if (f[0][v] < f[1][v]) { f[0][u] += f[0][v]; nn = min(nn, f[1][v] - f[0][v]); } else { has = true; f[0][u] += f[1][v]; } f[1][u] += min(f[0][v], min(f[2][v], f[1][v])); f[2][u] += min(f[0][v], f[1][v]); } if (!has) f[0][u] += nn; if (isLeaf) { f[0][u] = 1000111000; f[1][u] = 1; f[2][u] = 0; } } set< pair<int,int> > s; void solve(int u) { nReg = sz = top = 0; dfs1(u, -1); // PR(reg, n); // PR(ls, sz); FOR(i,1,nReg) { ke2[i].clear(); } s.clear(); FOR(t,1,sz) { int u = ls[t]; REP(i,ke[u].size()) { int v = ke[u][i]; if (reg[u] != reg[v] && s.find(MP(reg[u], reg[v])) == s.end()) { ke2[reg[u]].PB(reg[v]); ke2[reg[v]].PB(reg[u]); s.insert(MP(reg[u], reg[v])); s.insert(MP(reg[v], reg[u])); } } } if (nReg == 1) ++res; else { dfs2(1, -1); res += min(f[0][1], f[1][1]); // PR(f[0], nReg); // PR(f[1], nReg); // PR(f[2], nReg); } } int main() { scanf("%d%d", &n, &m); while (m--) { int u, v; scanf("%d%d", &u, &v); ke[u].PB(v); ke[v].PB(u); } FOR(i,1,n) if (!num[i]) { solve(i); } cout << res << endl; return 0; }
Code mẫu của skyvn97
#include<cstdio> #include<cstring> #include<queue> #include<vector> #define MAX 200200 #define FOR(i,a,b) for (int i=(a);i<=(b);i=i+1) #define REP(i,n) for (int i=0;i<(n);i=i+1) #define FORE(i,v) for (__typeof((v).begin()) i=(v).begin();i!=(v).end();i++) #define fi first #define se second using namespace std; const int INF=(int)1e6+7; typedef pair<int,int> ii; vector<ii> g[MAX]; vector<int> t[MAX]; bool blk[MAX]; bool isbr[MAX]; int m,n,nc,cnt; int p[MAX]; int id[MAX]; int low[MAX]; int num[MAX]; int f[MAX][4]; int min(int x,int y) { if (x<y) return (x); else return (y); } int min(int x,int y,int z) { return (min(x,min(y,z))); } int minimize(int &x,const int &y) { if (x>y) x=y; } int toblock(int id) { if (id%2==0) return (id-1); else return (id+1); } void loadgraph(void) { scanf("%d",&n); scanf("%d",&m); FOR(i,1,m) { int u,v; scanf("%d",&u); scanf("%d",&v); g[u].push_back(ii(v,2*i-1)); g[v].push_back(ii(u,2*i)); } } void visit(int u) { cnt++; low[u]=n+7; num[u]=cnt; FORE(it,g[u]) if (!blk[it->se]) { int v=it->fi; if (num[v]==0) { blk[toblock(it->se)]=true; visit(v); isbr[it->se]=(low[v]>num[u]); isbr[toblock(it->se)]=(low[v]>num[u]); minimize(low[u],low[v]); } else minimize(low[u],num[v]); } } void BFS(int s,int no) { queue<int> q; while (!q.empty()) q.pop(); q.push(s); id[s]=no; while (!q.empty()) { int u=q.front(); q.pop(); FORE(it,g[u]) if (!isbr[it->se]) if (id[it->fi]==0) { id[it->fi]=no; q.push(it->fi); } } } void loadtree(void) { FOR(i,1,n) if (num[i]==0) visit(i); FOR(i,1,n) if (id[i]==0) { nc++; BFS(i,nc); } FOR(i,1,n) FORE(it,g[i]) if (isbr[it->se]) { isbr[toblock(it->se)]=false; t[id[i]].push_back(id[it->fi]); t[id[it->fi]].push_back(id[i]); } memset(p,-1,sizeof p); } void dpvisit(int u) { bool leaf=true; FORE(it,t[u]) if (*it!=p[u]) { int v=*it; p[v]=u; dpvisit(v); leaf=false; } if (leaf) { f[u][0]=0; f[u][1]=INF; f[u][2]=1; return; } FORE(it,t[u]) if (*it!=p[u]) { if (f[*it][1]<INF) f[u][0]+=f[*it][1]; else { f[u][0]=INF; break; } } bool ok=false; int minadd=INF; FORE(it,t[u]) if (*it!=p[u]) { f[u][1]+=min(f[*it][1],f[*it][2]); if (f[*it][2]<=f[*it][1]) ok=true; minimize(minadd,f[*it][2]-f[*it][1]); } if (!ok) f[u][1]+=minadd; FORE(it,t[u]) if (*it!=p[u]) f[u][2]+=min(f[*it][0],f[*it][1],f[*it][2]); f[u][2]++; } void process(void) { int res=0; FOR(i,1,nc) if (p[i]<0) { p[i]=0; dpvisit(i); res+=min(f[i][1],f[i][2]); } printf("%d",res); } int main(void) { #ifndef ONLINE_JUDGE freopen("tmp.txt","r",stdin); #endif loadgraph(); loadtree(); process(); return 0; }
Bình luận