Comments

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  -3

  

  hieuminh0157  commented on June 19, 2024, 2:06 a.m.

  include <iostream>

  #include <cmath>
  
  std::string canArrangeMarbles(int n) {
      // Calculate the inverse of the triangular number formula
      double i = (std::sqrt(8 * static_cast<double>(n) + 1) - 1) / 2;
      // Check if i is an integer
      if (i == static_cast<int>(i)) {
          return "Yes.";
      } else {
          return "No.";
      }
  }
  
  int main() {
      int n;
      std::cin >> n;
      std::cout << canArrangeMarbles(n) << std::endl;
      return 0;
  }
  

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  1

  

  PizzaPasta  commented on Dec. 13, 2023, 11:31 a.m.

  sao minh dung cbrt() trg C++ ma wa v?

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  0

  

  tranhonghaidepzai2009  commented on July 9, 2024, 4:37 a.m.

  BẠN PHẢI LÀM TRÒN NỮA NHÉ

  include <iostream>

  include <math.h>

  using namespace std;

  define int long long

  int t; main() { ios::syncwithstdio(false); cin.tie(nullptr);cout.tie(nullptr);

  cin >> t;
  while(t--)
  {
      int n;
      cin >> n;
      if(round(cbrt(n)) * round(cbrt(n)) * round(cbrt(n)) == n)
          cout << "YES" << '\n';
      else
          cout << "NO" << '\n';
  }
  /* Trần Hồng Hải UwU */
  

  }

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  0

  

  tranhonghaidepzai2009  commented on July 9, 2024, 4:38 a.m.

  Đâu đó 0,006s thôi hihi >w<

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  0

  

  minhquantran  commented on July 26, 2023, 7:49 a.m.

  làm kiểu j v mọi người bằng ngôn ngữ python

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  6

  

  dylantamau  commented on Oct. 31, 2021, 12:38 p.m.

  HINT

  Sử dụng chặt nhị phân. Đặt ~mid = (L+R) \div 2~, nếu ~mid*mid*mid \le N~ thì ~L = mid + 1~, ngược lại ~R = mid -1~

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  0

  

  lehoanganh2008  commented on Dec. 9, 2022, 1:19 p.m.

  wdym?