Hướng dẫn giải của Bảng ô vuông


Chỉ dùng lời giải này khi không có ý tưởng, và đừng copy-paste code từ lời giải này. Hãy tôn trọng người ra đề và người viết lời giải.
Nộp một lời giải chính thức trước khi tự giải là một hành động có thể bị ban.

Lưu ý: Các code mẫu dưới đây chỉ mang tính tham khảo và có thể không AC được bài tập này

Code mẫu của happyboy99x

#include<algorithm>
#include<climits>
#include<cstdio>
#include<cstring>
using namespace std;

#define MAX 14
#define FOR(i, a, b) for(int i = (a), _b = (b); i <= _b; ++i)

int r, a[MAX+2][MAX+2], t[MAX+2][MAX+2];

void touch(int i, int j, int & cnt) {
    ++cnt;
    t[i][j] = 1 - t[i][j];
    t[i-1][j] = 1 - t[i-1][j];
    t[i+1][j] = 1 - t[i+1][j];
    t[i][j-1] = 1 - t[i][j-1];
    t[i][j+1] = 1 - t[i][j+1];
}

bool white() {
    FOR(i, 1, r) if(t[r][i]) return 0;
    return 1;
}

void solve() {
    int res = INT_MAX;
    FOR(fst, 0, (1 << r) - 1) {
        memcpy(t, a, sizeof a); int cnt = 0;
        FOR(i, 0, r-1) if(fst & (1 << i)) touch(1, i+1, cnt);
        FOR(i, 2, r) FOR(j, 1, r) if(t[i-1][j]) touch(i, j, cnt);
        if(white()) res = min(res, cnt);
    }
    FOR(i,1,r) FOR(j,1,r) a[i][j] = 1 - a[i][j];
    FOR(fst, 0, (1 << r) - 1) {
        memcpy(t, a, sizeof a); int cnt = 0;
        FOR(i, 0, r-1) if(fst & (1 << i)) touch(1, i+1, cnt);
        FOR(i, 2, r) FOR(j, 1, r) if(t[i-1][j]) touch(i, j, cnt);
        if(white()) res = min(res, cnt);
    }
    printf("%d\n", res == INT_MAX ? -1 : res);
}

void enter() {
    scanf("%d",&r); char s[MAX+2];
    FOR(i, 1, r) {
        scanf("%s", s+1);
        FOR(j, 1, r) a[i][j] = s[j] - 0x30;
    }
}

int main() {
#ifndef ONLINE_JUDGE
    freopen("input.txt", "r", stdin);
#endif
    enter();
    solve();
    return 0;
}

Code mẫu của ladpro98

program c11touch;
uses    math;
const   fi='';
        maxN=16;
var     a,d:array[0..maxN,0..maxN] of longint;
        n,res,target:longint;

procedure input;
var     f:text;
        i,j:longint;
        c:char;
begin
        assign(f,fi);
        reset(f);
        readln(f,n);
        for i:=1 to n do
        begin
                for j:=1 to n do
                begin
                        read(f,c);
                        a[i,j]:=ord(c)-48;
                end;
                readln(f);
        end;
        close(f);
end;

procedure update(k:longint);
var     i:longint;
begin
        for i:=1 to n do
        if d[n,i]<>target then exit;
        res:=k;
end;

procedure back(i,j,k:longint);
begin
        if k>=res then exit;
        if i>n then
        begin
                update(k);
                exit;
        end;
        if i=1 then
        begin
                if j<n then back(i,j+1,k)
                else back(i+1,1,k);
                d[i-1,j]:=d[i-1,j] xor 1;
                d[i,j]:=d[i,j] xor 1;
                d[i,j-1]:=d[i,j-1] xor 1;
                d[i,j+1]:=d[i,j+1] xor 1;
                d[i+1,j]:=d[i+1,j] xor 1;
                if j<n then back(i,j+1,k+1)
                else back(i+1,1,k+1);
                d[i-1,j]:=d[i-1,j] xor 1;
                d[i,j]:=d[i,j] xor 1;
                d[i,j-1]:=d[i,j-1] xor 1;
                d[i,j+1]:=d[i,j+1] xor 1;
                d[i+1,j]:=d[i+1,j] xor 1;
        end
        else
        begin
                if d[i-1,j]=target then
                if j<n then back(i,j+1,k)
                else back(i+1,1,k)
                else
                begin
                        d[i-1,j]:=d[i-1,j] xor 1;
                        d[i,j]:=d[i,j] xor 1;
                        d[i,j-1]:=d[i,j-1] xor 1;
                        d[i,j+1]:=d[i,j+1] xor 1;
                        d[i+1,j]:=d[i+1,j] xor 1;
                        if j<n then back(i,j+1,k+1)
                        else back(i+1,1,k+1);
                        d[i-1,j]:=d[i-1,j] xor 1;
                        d[i,j]:=d[i,j] xor 1;
                        d[i,j-1]:=d[i,j-1] xor 1;
                        d[i,j+1]:=d[i,j+1] xor 1;
                        d[i+1,j]:=d[i+1,j] xor 1;
                end;
        end;
end;

procedure process;
begin
        res:=maxLongint;
        d:=a;
        target:=0;
        back(1,1,0);
        d:=a;
        target:=1;
        back(1,1,0);
        if res=maxLongint
        then res:=-1;
end;

begin
        input;
        process;
        write(res);
end.

Code mẫu của RR

#include <sstream>
#include <iomanip>
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <stack>
#include <queue>
#include <string>
#include <deque>
#include <complex>

#define FOR(i,a,b) for(int i=(a),_b=(b); i<=_b; i++)
#define FORD(i,a,b) for(int i=(a),_b=(b); i>=_b; i--)
#define REP(i,a) for(int i=0,_a=(a); i<_a; i++)
#define FORN(i,a,b) for(int i=(a),_b=(b);i<_b;i++)
#define DOWN(i,a,b) for(int i=a,_b=(b);i>=_b;i--)
#define SET(a,v) memset(a,v,sizeof(a))
#define sqr(x) ((x)*(x))
#define ll long long
#define F first
#define S second
#define PB push_back
#define MP make_pair

#define DEBUG(x) cout << #x << " = "; cout << x << endl;
#define PR(a,n) cout << #a << " = "; FOR(_,1,n) cout << a[_] << ' '; cout << endl;
#define PR0(a,n) cout << #a << " = "; REP(_,n) cout << a[_] << ' '; cout << endl;
using namespace std;

//Buffer reading
int INP,AM,REACHEOF;
#define BUFSIZE (1<<12)
char BUF[BUFSIZE+1], *inp=BUF;
#define GETCHAR(INP) { \
    if(!*inp) { \
        if (REACHEOF) return 0;\
        memset(BUF,0,sizeof BUF);\
        int inpzzz = fread(BUF,1,BUFSIZE,stdin);\
        if (inpzzz != BUFSIZE) REACHEOF = true;\
        inp=BUF; \
    } \
    INP=*inp++; \
}
#define DIG(a) (((a)>='0')&&((a)<='9'))
#define GN(j) { \
    AM=0;\
    GETCHAR(INP); while(!DIG(INP) && INP!='-') GETCHAR(INP);\
    if (INP=='-') {AM=1;GETCHAR(INP);} \
    j=INP-'0'; GETCHAR(INP); \
    while(DIG(INP)){j=10*j+(INP-'0');GETCHAR(INP);} \
    if (AM) j=-j;\
}
//End of buffer reading

const long double PI = acos((long double) -1.0);

#define TWO(x) (1<<(x))
#define CONTAIN(S,x) (S & TWO(x))
;

int n, res, now;
char a[111][111];
int c[111];

inline void flip(int i, int j) {
    ++now;
    if (i) c[i-1] ^= TWO(j);
    if (i+1 < n) c[i+1] ^= TWO(j);
    c[i] ^= TWO(j);
    if (j) c[i] ^= TWO(j-1);
    if (j+1 < n) c[i] ^= TWO(j+1);
}

void update(int s) {
    REP(i,n) {
        c[i] = 0;
        REP(j,n)
            if (a[i][j] == '1') c[i] |= TWO(j);
    }

    now = 0;
    REP(j,n) if (CONTAIN(s,j)) {
        flip(0,j);
    }

    FOR(i,1,n-1) REP(j,n)
    if (CONTAIN(c[i-1], j)) {
        flip(i, j);
    }
    if (c[n-1]) return ;
    res = min(res, now);
}

int main() {
    scanf("%d\n", &n);
    REP(i,n) gets(a[i]);

    res = n*n+1;

    REP(turn,2) {
        REP(s,TWO(n)) update(s);

        REP(i,n) REP(j,n)
            if (a[i][j] == '1') a[i][j] = '0';
            else a[i][j] = '1';
    }
    if (res > n*n) res = -1;
    printf("%d\n", res);
    return 0;
}

Code mẫu của hieult

#include <set>
#include <map>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <cctype>
#include <cstdio>
#include <string>
#include <vector>
#include <cassert>
#include <cstdlib>
#include <cstring>
#include <sstream>
#include <iomanip>
#include <iostream>
#include <algorithm>

using namespace std;

typedef long long ll;
typedef long double ld;
typedef unsigned int ui;
typedef unsigned long long ull;

#define Rep(i,n) for(__typeof(n) i = 0; i < (n); ++i)
#define Repd(i,n) for(__typeof(n) i = (n)-1; i >= 0; --i)
#define For(i,a,b) for(__typeof(b) i = (a); i <= (b); ++i)
#define Ford(i,a,b) for(__typeof(a) i = (a); i >= (b); --i)
#define Fit(i,v) for(__typeof((v).begin()) i = (v).begin(); i != (v).end(); ++i)
#define Fitd(i,v) for(__typeof((v).rbegin()) i = (v).rbegin(); i != (v).rend(); ++i)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define sz(a) ((int)(a).size())
#define all(a) (a).begin(), (a).end()
#define ms(a,x) memset(a, x, sizeof(a))
#define nl puts("")
#define sp printf(" ")
#define ok puts("ok")
//#include <conio.h>

template<class F, class T> T convert(F a, int p = -1) { stringstream ss; if (p >= 0) ss << fixed << setprecision(p); ss << a; T r; ss >> r; return r; }
template<class T> void db(T a, int p = -1) { if (p >= 0) cout << fixed << setprecision(p); cout << a << " "; }
template<class T> T gcd(T a, T b) { T r; while (b != 0) { r = a % b; a = b; b = r; } return a; }
template<class T> T lcm(T a, T b) { return a / gcd(a, b) * b; }
template<class T> T sqr(T x) { return x * x; }
template<class T> T cube(T x) { return x * x * x; }
template<class T> struct Triple { T x, y, z; Triple() {} Triple(T _x, T _y, T _z) : x(_x), y(_y), z(_z) {} };
template<class T> Triple<T> euclid(T a, T b) { if (b == 0) return Triple<T>(1, 0, a); Triple<T> r = euclid(b, a % b); return Triple<T>(r.y, r.x - a / b * r.y, r.z); }
template<class T> int getbit(T s, int i) { return (s >> i) & 1; }
template<class T> T onbit(T s, int i) { return s | (T(1) << i); }
template<class T> T offbit(T s, int i) { return s & (~(T(1) << i)); }
template<class T> int cntbit(T s) { return s == 0 ? 0 : cntbit(s >> 1) + (s & 1); }
const int bfsz = 1 << 16; char bf[bfsz + 5]; int rsz = 0;int ptr = 0;
char gc() { if (rsz <= 0) { ptr = 0; rsz = fread(bf, 1, bfsz, stdin); if (rsz <= 0) return EOF; } --rsz; return bf[ptr++]; }
void ga(char &c) { c = EOF; while (!isalpha(c)) c = gc(); }
int gs(char s[]) { int l = 0; char c = gc(); while (isspace(c)) c = gc(); while (c != EOF && !isspace(c)) { s[l++] = c; c = gc(); } s[l] = '\0'; return l; }
template<class T> bool gi(T &v) {
    v = 0; char c = gc(); while (c != EOF && c != '-' && !isdigit(c)) c = gc(); if (c == EOF) return false; bool neg = c == '-'; if (neg) c = gc();
    while (isdigit(c)) { v = v * 10 + c - '0'; c = gc(); } if (neg) v = -v; return true;
}

const double PI = 2 * acos(0);
const string months[] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
const int dr[] = {0, 0, 0, -1, +1};
const int dc[] = {0, -1, +1, 0, 0};
const int inf = (int)1e9 + 5;
const ll linf = (ll)1e16 + 5;
const double eps = ld(1e-12);
const ll mod = 1000000000;
typedef pair<int, int> II;

#define maxn 100005

using namespace std;

int n;
string s[20];
int x[20][20], a[15][15];

bool thoaman(int r, int c){
    return (r >= 0 && r < n && c >= 0 && c < n);
}

int cal(int r, int c){
    int rr, cc, res = 0;
    Rep(t, 5){
        rr = r + dr[t]; cc = c + dc[t];
        if(thoaman(rr, cc)) res += a[rr][cc];
    }
    return res & 1;
}

int go(int mask){
    ms(a, 0);
    int res = cntbit(mask);
    Rep(i, n) if(getbit(mask, i)) a[0][i] = 1;
    Rep(i, n - 1) Rep(j, n){
        a[i + 1][j] = cal(i, j) ^ x[i][j];
        res += a[i + 1][j];
    }

    Rep(i, n) if(cal(n - 1, i) ^ x[n - 1][i]) return inf;
    return res;
}

int main(){
//    freopen("in.txt", "r", stdin);
//    freopen("out.txt", "w", stdout);
    scanf("%d", &n);
    Rep(i, n){
        cin >> s[i];
        Rep(j, n) x[i][j] = s[i][j] - '0';
    }

    int res = inf;
    Rep(run, 1 << n){
        res = min(res, go(run));
    }

    Rep(i, n) Rep(j, n) x[i][j] = 1 - x[i][j];
    Rep(run, 1 << n){
        res = min(res, go(run));
    }

    if(res < inf) printf("%d", res);
    else printf("-1");
   // cout << clock() << endl;
    return 0;
}

Code mẫu của skyvn97

#include<stdio.h>
#define MAX   20
#define INF   100000
int x[MAX][MAX];
char a[MAX][MAX];
int n,m;
void init(void)
{
     int i,j;
     scanf("%d",&n);
     for (i=1;i<=n;i=i+1)
         scanf("%s",&a[i]);
     for (i=1;i<=n;i=i+1)
         for (j=n;j>=1;j=j-1)
             {
              a[i][j]=a[i][j-1]-48;     
              x[i][j]=0;
             }     
     m=INF;
}
void change(int x,int y)
{
     a[x-1][y]=1-a[x-1][y];
     a[x][y-1]=1-a[x][y-1];
     a[x+1][y]=1-a[x+1][y];
     a[x][y+1]=1-a[x][y+1];
     a[x][y]=1-a[x][y];
}
void count(int v)
{
     int i,j,c;
     bool b;
     b=true;
     c=0;
     for (i=1;i<=n;i=i+1)
         if (x[1][i]==1)
            {
             change(1,i);
             c=c+1;
            }
     for (i=2;i<=n;i=i+1)
         for (j=1;j<=n;j=j+1)
             if (a[i-1][j]!=v)
                {
                 x[i][j]=1;
                 change(i,j);
                 c=c+1;
                }             
     for (i=1;i<=n;i=i+1)
         if (a[n][i]!=v)
            {
             b=false;
             break;
            }     
     if ((b) && (c<m)) m=c;     
     for (i=1;i<=n;i=i+1)     
         for (j=1;j<=n;j=j+1)
             if (x[i][j]==1)
                {
                 if (i>1) x[i][j]=0;
                 change(i,j);
                }
}
void btrk(int k,int v)
{
     int i;
     for (i=0;i<=1;i=i+1)
         {
          x[1][k]=i;
          if (k==n) count(v);
          else btrk(k+1,v);
         }
}
void process(void)
{
     init();    
     btrk(1,0);
     btrk(1,1);
     if (m>=INF) printf("-1");
     else printf("%d",m);
}
int main(void)
{
    process();
}

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