Hướng dẫn giải của BARICA


Chỉ dùng lời giải này khi không có ý tưởng, và đừng copy-paste code từ lời giải này. Hãy tôn trọng người ra đề và người viết lời giải.
Nộp một lời giải chính thức trước khi tự giải là một hành động có thể bị ban.

Lưu ý: Các code mẫu dưới đây chỉ mang tính tham khảo và có thể không AC được bài tập này

Code mẫu của flashmt

const maxn=100010;
var n,k:longint;
    x,y,a,d,f:array[1..maxn] of longint;
    maxcol:array[0..maxn] of longint;

procedure rf;
var i:longint;
begin
     read(n,k);
     for i:=1 to n do
     begin
          read(x[i],y[i],a[i]);
          d[i]:=i;
     end;
end;

procedure sort(l,r:longint);
var i,j,t,u,v:longint;
begin
     i:=l; j:=r; t:=x[(i+j) shr 1]; v:=y[(i+j) shr 1];
     repeat
           while (x[i]<t) or ((x[i]=t) and (y[i]<v)) do i:=i+1;
           while (x[j]>t) or ((x[j]=t) and (y[j]>v)) do j:=j-1;
           if i<=j then
           begin
                u:=d[i]; d[i]:=d[j]; d[j]:=u;
                u:=x[i]; x[i]:=x[j]; x[j]:=u;
                u:=y[i]; y[i]:=y[j]; y[j]:=u;
                u:=a[i]; a[i]:=a[j]; a[j]:=u;
                i:=i+1; j:=j-1;
           end;
     until i>j;
     if i<r then sort(i,r);
     if l<j then sort(l,j);
end;

function max(u,v:longint):longint;
begin
     if u>v then max:=u else max:=v;
end;

procedure pr;
var i,t,u,maxrow:longint;
begin
     sort(1,n);
     for i:=1 to n do f[i]:=-1;
     for i:=0 to maxn div 3 do maxcol[i]:=-1;
     for t:=1 to n do
         if d[t]=1 then break;
     f[t]:=a[t]; maxcol[y[t]]:=a[t]; maxrow:=a[t]; inc(t);
     while true do
     begin
          if x[t]=x[t-1] then
          begin
               if maxrow>=k then
                  f[t]:=max(f[t],maxrow-k+a[t]);
          end;
          if maxcol[y[t]]>=k then
             f[t]:=max(f[t],maxcol[y[t]]-k+a[t]);
          if x[t]=x[t-1] then maxrow:=max(maxrow,f[t])
          else maxrow:=f[t];
          maxcol[y[t]]:=max(maxcol[y[t]],f[t]);
          if d[t]=n then break;
          t:=t+1;
     end;
     writeln(f[t]);
end;

begin
     rf;
     pr;
end.

Code mẫu của happyboy99x

#include<cstdio>
#include<algorithm>
using namespace std;

const int N = 300000 + 5, XY = 100000 + 5, INF = 1000000000;
struct plant {
    int x, y, f, id;
    bool operator < (const plant &o) const {
        return x < o.x || x == o.x && y < o.y;
    }
} p[N];
int n, k, maxX[XY], maxY[XY], f[N];

void enter() {
    scanf("%d%d", &n, &k);
    for(int i = 1; i <= n; ++i) {
        scanf("%d%d%d", &p[i].x, &p[i].y, &p[i].f);
        p[i].id = i;
    }
}

void solve() {
    sort(p+1, p+n+1); f[0] = -INF;
    for(int i = 1; i <= n; ++i) {
        int id = p[i].id;
        f[id] = -INF; if(id == 1) f[id] = p[i].f;
        int xx = maxX[p[i].x], yy = maxY[p[i].y];
        if(f[xx] >= k && f[xx] - k + p[i].f > f[id]) f[id] = f[xx] - k + p[i].f;
        if(f[yy] >= k && f[yy] - k + p[i].f > f[id]) f[id] = f[yy] - k + p[i].f;
        if(f[id] > f[xx]) maxX[p[i].x] = id;
        if(f[id] > f[yy]) maxY[p[i].y] = id;
    }
    printf("%d\n", f[n]);
}

int main() {
    enter();
    solve();
    return 0;
}

Code mẫu của ladpro98

program baricavn;//dp
uses    math;
type    e=record
        x,y,p,s:longint;
        end;
const   maxn=300005;
        maxV=100005;
        fi='';
var     a:array[1..maxn] of e;
        maxCol,maxRow:array[0..maxV] of longint;
        n,k:longint;

procedure input;
var     inp:text;
        i:longint;
begin
        assign(inp,fi);
        reset(inp);
        readln(inp,n,k);
        for i:=1 to n do
        begin
                readln(inp,a[i].x,a[i].y,a[i].s);
                a[i].p:=i;
        end;
        close(inp);
end;

procedure swap(i,j:longint);
var     t:e;
begin
        t:=a[i];
        a[i]:=a[j];
        a[j]:=t;
end;


procedure sort(l,r:longint);
var     i,j:longint;
        p:e;
begin
        if l>=r then exit;
        i:=l;j:=r;
        p:=a[random(r-l+1)+l];
        repeat
                while (a[i].x<p.x) or ((a[i].x=p.x) and (a[i].y<p.y)) do inc(i);
                while (a[j].x>p.x) or ((a[j].x=p.x) and (a[j].y>p.y)) do dec(j);
                if i<=j then
                begin
                        if i<j then swap(i,j);
                        inc(i);
                        dec(j);
                end;
        until i>j;
        sort(l,j);
        sort(i,r);
end;

procedure dp;
var     j,i,t,lx,ly:longint;
begin
        for j:=1 to n do
        if a[j].p=1 then
        begin
                maxRow[a[j].x]:=a[j].s;
                maxCol[a[j].y]:=a[j].s;
                lx:=a[j].x;ly:=a[j].y;
                for i:=j+1 to n do
                if (a[i].x>=lx) and (a[i].y>=ly) then
                if max(maxRow[a[i].x],maxCol[a[i].y])>=k then
                begin
                        t:=max(maxRow[a[i].x],maxCol[a[i].y])-k+a[i].s;
                        if a[i].p=n then
                        begin
                                writeln(t);
                                exit;
                        end;
                        maxRow[a[i].x]:=max(maxRow[a[i].x],t);
                        maxCol[a[i].y]:=max(maxCol[a[i].y],t);
                end;
        end;
end;

begin
        input;
        sort(1,n);
        dp;
end.

Code mẫu của RR

#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <set>

#define MAXN 300111
#define FOR(i,a,b) for(long i=a; i<=b; i++)
#define S set< pair<long,long> >
#define FORS(s,i) for(S::iterator i=s.begin(); i!=s.end(); i++)
#define MP make_pair

using namespace std;
long n,k,targetu,targetv,startu,startv,maxX[MAXN],maxY[MAXN],f[MAXN];
pair< pair<long,long>,long> a[MAXN];
S s;

void inp() {
     scanf("%ld %ld",&n,&k);
     FOR(i,1,n)
       scanf("%ld %ld %ld",&a[i].first.first,&a[i].first.second,&a[i].second);
}

void RR() {
     //Roi rac hoa theo truc X
     FOR(i,1,n)
       s.insert(MP(a[i].first.first,i));
     long now=s.begin()->first,ind=1;
     a[s.begin()->second].first.first=1;
     FORS(s,i)
     if (i!=s.begin()) {
                       if (i->first!=now) {
                                          ind++;
                                          now=i->first;
                       }
                       a[i->second].first.first=ind;
     }
     //Roi rac hoa theo truc Y
     s.clear();
     FOR(i,1,n) 
       s.insert(MP(a[i].first.second,i));
     now=s.begin()->first; ind=1;
     a[s.begin()->second].first.second=1;
     FORS(s,i)
     if (i!=s.begin()) {
                       if (i->first!=now) {
                                          ind++;
                                          now=i->first;
                       }
                       a[i->second].first.second=ind;
     }
}

void solve() {
     targetu=a[n].first.first;
     targetv=a[n].first.second;
     startu=a[1].first.first;
     startv=a[1].first.second;

     sort(a+1,a+n+1);
     FOR(i,1,n) {
                if (a[i].first.first==startu&&a[i].first.second==startv) {
                       f[i]=a[i].second;
                       maxX[a[i].first.first]=f[i];
                       maxY[a[i].first.second]=f[i];
                } else {
                       long temp=max(maxX[a[i].first.first],maxY[a[i].first.second])-k;
                       if (temp>=0) temp+=a[i].second; else temp=0;
                       f[i]=temp;
                       maxX[a[i].first.first]>?=f[i];
                       maxY[a[i].first.second]>?=f[i];
                }
     }
     FOR(i,1,n)
       if (a[i].first.first==targetu&&a[i].first.second==targetv)
         printf("%ld\n",f[i]);
}

int main() {
    #ifdef DEBUG
      freopen("input.txt","r",stdin);
      freopen("output.txt","w",stdout);
    #endif
    inp();
    RR();
    solve();
    return 0;
}

Code mẫu của hieult

#include <set>
#include <map>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <bitset>
#include <cctype>
#include <cstdio>
#include <string>
#include <vector>
#include <cassert>
#include <cstdlib>
#include <cstring>
#include <sstream>
#include <iomanip>
#include <iostream>
#include <algorithm>

using namespace std;

typedef long long ll;
typedef long double ld;
typedef unsigned int ui;
typedef unsigned long long ull;

#define Rep(i,n) for(typeof(n) i = 0; i < (n); ++i)
#define Repd(i,n) for(typeof(n) i = (n)-1; i >= 0; --i)
#define For(i,a,b) for(typeof(b) i = (a); i <= (b); ++i)
#define Ford(i,a,b) for(typeof(a) i = (a); i >= (b); --i)
#define Fit(i,v) for(typeof((v).begin()) i = (v).begin(); i != (v).end(); ++i)
#define Fitd(i,v) for(typeof((v).rbegin()) i = (v).rbegin(); i != (v).rend(); ++i)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define sz(a) ((int)(a).size())
#define all(a) (a).begin(), (a).end()
#define ms(a,x) memset(a, x, sizeof(a))
#define nl puts("")
#define sp printf(" ")
#define ok puts("ok")
//#include <conio.h>

template<class F, class T> T convert(F a, int p = -1) { stringstream ss; if (p >= 0) ss << fixed << setprecision(p); ss << a; T r; ss >> r; return r; }
template<class T> void db(T a, int p = -1) { if (p >= 0) cout << fixed << setprecision(p); cout << a << " "; }
template<class T> T gcd(T a, T b) { T r; while (b != 0) { r = a % b; a = b; b = r; } return a; }
template<class T> T lcm(T a, T b) { return a / gcd(a, b) * b; }
template<class T> T sqr(T x) { return x * x; }
template<class T> T cube(T x) { return x * x * x; }
template<class T> struct Triple { T x, y, z; Triple() {} Triple(T _x, T _y, T _z) : x(_x), y(_y), z(_z) {} };
template<class T> Triple<T> euclid(T a, T b) { if (b == 0) return Triple<T>(1, 0, a); Triple<T> r = euclid(b, a % b); return Triple<T>(r.y, r.x - a / b * r.y, r.z); }
template<class T> int getbit(T s, int i) { return (s >> i) & 1; }
template<class T> T onbit(T s, int i) { return s | (T(1) << i); }
template<class T> T offbit(T s, int i) { return s & (~(T(1) << i)); }
template<class T> int cntbit(T s) { return s == 0 ? 0 : cntbit(s >> 1) + (s & 1); }
const int bfsz = 1 << 16; char bf[bfsz + 5]; int rsz = 0;int ptr = 0;
char gc() { if (rsz <= 0) { ptr = 0; rsz = fread(bf, 1, bfsz, stdin); if (rsz <= 0) return EOF; } --rsz; return bf[ptr++]; }
void ga(char &c) { c = EOF; while (!isalpha(c)) c = gc(); }
int gs(char s[]) { int l = 0; char c = gc(); while (isspace(c)) c = gc(); while (c != EOF && !isspace(c)) { s[l++] = c; c = gc(); } s[l] = '\0'; return l; }
template<class T> bool gi(T &v) {
    v = 0; char c = gc(); while (c != EOF && c != '-' && !isdigit(c)) c = gc(); if (c == EOF) return false; bool neg = c == '-'; if (neg) c = gc();
    while (isdigit(c)) { v = v * 10 + c - '0'; c = gc(); } if (neg) v = -v; return true;
}

const double PI = 2 * acos(0);
const string months[] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
const int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
const int dr[] = {-1, 0, +1, 0};
const int dc[] = {0, +1, 0, -1};
const int inf = (int)1e9 + 5;
const ll linf = (ll)1e16 + 5;
const double eps = 1e-9;
const ll mod = 100000007;
typedef pair<int, int> II;

#define maxn 300005

pair<II, II> A[maxn];
int n, k, fx[maxn], fy[maxn], f[maxn];

int main() {
//    freopen("in.txt", "r", stdin);
//    freopen("out.txt", "w", stdout);
    ms(f, -1); ms(fx, -1); ms(fy, -1);
    gi(n); gi(k);
    Rep(i, n){
        gi(A[i].fi.fi); gi(A[i].fi.se); gi(A[i].se.fi);
        A[i].se.se = i + 1;
    }
    sort(A, A + n);
    bool flag = false;
    int x, y, num, id, t;
    Rep(i, n){

        if(!flag && A[i].se.se != 1) continue;
        x = A[i].fi.fi; y = A[i].fi.se; num = A[i].se.fi; id = A[i].se.se;
        if(A[i].se.se == 1){
            flag = true;
            fx[x] = max(fx[x], num);
            fy[y] = max(fy[y], num);
            continue;
        }
        t = max(fx[x], fy[y]);
        if(t < k) continue;
        fx[x] = max(fx[x], t - k + num);
        fy[y] = max(fy[y], t - k + num);
        if(id == n){
            printf("%d", t - k + num);
            return 0;
        }
    }
}

Code mẫu của ll931110

{$MODE DELPHI}
program BARICAVN;
uses math;
const
  input  = '';
  output = '';
  maxn = 300000;
  maxt = 100000;
type
  rec = record
    x,y,val,pos: integer;
  end;
var
  a: array[1..maxn] of rec;
  maxx,maxy: array[0..maxt] of integer;
  n,k: integer;

procedure init;
var
  f: text;
  i: integer;
begin
  assign(f, input);
    reset(f);

  readln(f, n, k);
  for i := 1 to n do
    begin
      readln(f, a[i].x,a[i].y,a[i].val);
      a[i].pos := i;
    end;

  close(f);
end;

procedure swap(var u,v: rec);
var
  z: rec;
begin
  z := u;  u := v;  v := z;
end;

function lower(u,v: rec): boolean;
begin
  lower := (u.x < v.x) or ((u.x = v.x) and (u.y < v.y));
end;

procedure quicksort;

  procedure par(l,h: integer);
  var
    i,j: integer;
    p: rec;
  begin
    if l >= h then exit;
    i := l; j := h; p := a[random(h - l + 1) + l];

    repeat
      while lower(a[i],p) do inc(i);
      while lower(p,a[j]) do dec(j);

      if i <= j then
        begin
          if i < j then swap(a[i],a[j]);
          inc(i);
          dec(j);
        end;
    until i > j;

    par(l,j);
    par(i,h);
  end;

begin
  par(1,n);
end;

procedure solve;
var
  f: text;
  i,t: integer;
begin
  for i := 0 to maxt do
    begin
      maxx[i] := -maxn;
      maxy[i] := -maxn;
    end;

  i := 1;
  while a[i].pos <> 1 do inc(i);
  maxx[a[i].x] := a[i].val;
  maxy[a[i].y] := a[i].val;

  repeat
    inc(i);
    t := max(maxx[a[i].x],maxy[a[i].y]);
    if t >= k then t := t - k + a[i].val;
    if maxx[a[i].x] < t then maxx[a[i].x] := t;
    if maxy[a[i].y] < t then maxy[a[i].y] := t;
  until a[i].pos = n;

  assign(f, output);
    rewrite(f);
    writeln(f, t);
  close(f);
end;

begin
  init;
  quicksort;
  solve;
end.

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